Webpublic static byte [] ZipFiles (Dictionary files) { using (MemoryStream ms = new MemoryStream ()) { using (ZipArchive archive = new ZipArchive (ms, ZipArchiveMode.Update)) { foreach (var file in files) { ZipArchiveEntry orderEntry = archive.CreateEntry (file.Key); //create a file with this name using (BinaryWriter writer = … Webprivate static Stream CreateZipStream (FileForZip [] files) { var s = new MemoryStream (); using (var archive = new ZipArchive (s, ZipArchiveMode.Update, true)) { foreach (var file in files) { var entry = archive.CreateEntry (file.Filename); using (var w = new StreamWriter (entry.Open ())) { w.Write (file.Content); } if (file.ModifiedTime.HasValue)

C# 从字节[]创建zip文件_C#_.net_Asp.net Mvc_Zip_.net 4.5 - 多多扣

http://duoduokou.com/csharp/17707127109767100809.html WebApr 23, 2024 · Thanks for the reply... I tried out your solution on a zip file with several thousand files inside of it and it is not thread safe either. The race condition doesn't show up in 4 files but by a thousand or so it hits pretty This isn't too surprising since MS claims IO classes are not thread safe by default... hence then use of Stream.Synchronized. assura ya-r18a データ更新

ZipArchive.CreateEntry for a Stream

WebCreates an empty entry that has the specified path and entry name in the zip archive. C# public System.IO.Compression.ZipArchiveEntry CreateEntry (string entryName); Parameters entryName String A path, relative to the root of the archive, that specifies the name of the entry to be created. Returns ZipArchiveEntry An empty entry in the zip archive. Webusing (var compressedFileStream = new MemoryStream()) { //Create an archive and store the stream in memory. using (var zipArchive = new … WebThe following example shows how to create a new entry, open it with the Open method, and write to the stream. C#. using System; using System.IO; using … assura-basis ag