WebAnswer (1 of 5): x^3-y^3=(x-y)(x^2+xy+y^2) 8x^3–27=(2x)^3–3^3=(2x-3)(4x^2+6x+9) WebQuestion 384876: Factor completely. 8x^3 - 27 Found 2 solutions by ewatrrr, fcabanski: Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website! Hi, Factoring completely 8x^3 - 27 = (2x)^3 - 3^2 In general: x^3 - a^3 = (x-a)(x^2 -ax + a^2)

SOLUTION: Factor completely. 8x^3 - 27 - Algebra

WebHow do you factor completely 8y^3 + 27? How do you factor 2x^3 + 6x^2 + 5x? How do you factor x^2 - 16? How do you factor b^2 - 21b + 38? How do you factor 6x^2 - 5x - 6? How do you factor x^3 - x^2 + x -6? How do you factor x^3 + x^2 - x - 1? How do you factor w^4 - 625? How do you factor 8x^2 - 11x + 3? How do you factor z^3 - 4? WebFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. dict string python

How do you factor x^6 - 1? Socratic

WebFactoring Calculator. Enter the expression you want to factor in the editor. The Factoring Calculator transforms complex expressions into a product of simpler factors. It can … WebTo factor a trinomial x^2+bx+c find two numbers u, v that multiply to give c and add to b. Rewrite the trinomial as the product of two binomials (x-u) (x-v) city fitness cancellation fee